25x^2-4/5x+2

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Solution for 25x^2-4/5x+2 equation: 


x in (-oo:+oo)

25*x^2-((4/5)*x)+2 = 0

25*x^2+(-4/5)*x+2 = 0

25*x^2-4/5*x+2 = 0

DELTA = (-4/5)^2-(2*4*25)

DELTA = -4984/25

DELTA < 0

x belongs to the empty set

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